Is anyone good with word problems?

Question

a rectangle garden has perimeter 66 ft and area 216ft sq. find the dimmensions of the garden. does any one know how to do this???

Answer 1

long sides are 24ft and short sides are 9ft.

Area = width x lenth
216 = 24 x 9

Dimensions 24+24+9+9 = 66

Answer 2

First, you need the formula for perimeter of a rectangle:

2L + 2W = 66, where the perimeter is the sum of the 4 sides, L is the length and W is the width.

Then the area of the rectangle is L x W = 216.

Now you have two equations with two unknowns.

Us substitution for the area using the perimeter:
2L = 66 - 2W, so L = 33 - W

Therefore, L x W = (33 - W) x W = 33W - W^2 = 216.

This looks like a quadratic equation,
let's put in the form ax^2 + bx + c = 0

W^2 -33W + 216 = 0

Find two numbers whose sum is -33 and whose product is 216, should be two negative numbers, you'll get -9 and -24:

(W - 9)(W - 24) = 0, possible widths are 9 and 24.

But note 2x9 + 2x24 = 18 + 48 = 66.

9 and 24.

Answer 3

the rectangle is 9 by 24
9+9+24+24=66 and 9x24=216

Answer 4

let a and b be the two dimensions of the rectangle
a + b = 66/2 = 33
a*b = 216
so a and b are the two roots of this equation : X^2 - 33X + 216 = 0
solve the equation we have x1= 24, x2=9

Answer 5

24 x 9
Take half the circumference (33') and try things like 25 x 8, 24 x 9, 23 x 10 with the sum of the two number you try adding up to in this case 33

Answer 6

let x = length , y = wide
2x + 2y = 66 perimeter
xy = 216 area

then use system equation to solve for x and y.

Answer 7

2x + 2y = 66
xy=216

graph then find (x,y) where they intercept

You get two points of intersection, (9,24) and (24,9)

so dimensions are 9 x 24

Answer 8

multiply 66 and 216 together....... pretty sure

Answer 9

No Idea!Sry!