I put "a" where the trigonometry symbol should go... please help. Thanks!
2006-11-28 13:21:30 · 6 answers · asked by Min 1 in Science & Mathematics ➔ Mathematics
One way to do this is to remember that:
tan = sin/cos
So tan(a) = sin(a) / cos(a)
= (12/13)/(5/13) = 12/5 or 2.4
We could actually construct the triangle and we'd find that it is a 5-12-13 right triangle with the side of length 12 opposite angle a and the side of length 5 adjacent to angle a.
Here, tan(a) = opposite/adjacent = 12/5 or 2.4
2006-11-28 13:24:44 · answer #1 · answered by hokiejthweatt 3 · 0⤊ 0⤋
Tan a=12/5
2006-11-28 21:25:19 · answer #2 · answered by Dead Dog 2 · 0⤊ 0⤋
12/5
2006-11-28 21:23:43 · answer #3 · answered by zeromeyzl 2 · 0⤊ 0⤋
A basic trig identity is
tan a = sin a/cos a
So Tan a = (12/13)/(5/13) = (12/13)(13/5) = 12/5
2006-11-28 21:26:37 · answer #4 · answered by kindricko 7 · 0⤊ 0⤋
tan= sin/cos (12/13)/(5/13)= 12/5
2006-11-28 21:25:29 · answer #5 · answered by steaua 3 · 0⤊ 0⤋
tan = sin/cos = 12/5
2006-11-28 21:23:10 · answer #6 · answered by alwayss_ready 3 · 0⤊ 0⤋