English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

y^2+y-30 im trying to findhow y will equal 0 and another number its quadratics

2006-11-28 12:39:05 · 4 answers · asked by king_13d 1 in Science & Mathematics Mathematics

4 answers

If it equals zero, use FOIL: (y+6)(y-5) = 0

so y = -6 or 5 [since -6 + 6 is zero and so is 5 - 5]

If it equals another number, subtract that from both sides to make it equal zero then use FOIL (or quadratic formula)

Example: y^2 + y - 30 = 12

y^2 + y - 30 - 12 = 12 - 12

y^2 + y - 42 = 0

(y+7)(y-6) = 0

y = -7 or 6

2006-11-28 12:45:44 · answer #1 · answered by hayharbr 7 · 0 0

(y+6)(y-5) = 0
y = -6, 5

If you know the quadratic formula, you can get the right answer every time but i would highly recommend some practice in doing these by just string at them. This becomes quite handy.

2006-11-28 20:44:33 · answer #2 · answered by Morkeleb 3 · 0 0

y^2+y-30 factors to (y+6)(y-5)
y=5; y=-6

2006-11-28 20:49:59 · answer #3 · answered by Steve A 7 · 0 0

I'm not sure i understand your wording.
do you want to solve for y^2 + y -30 = 0?

2006-11-28 20:51:06 · answer #4 · answered by Jess 2 · 0 0

fedest.com, questions and answers