2006-11-28 12:09:00 · 6 answers · asked by Kamikaze Pilot 2 in Science & Mathematics ➔ Mathematics
Substitute y(0)=1 into y= -1/(-cos x + c)
1 = -1/(-cos0 + c)
1 = -1/(-1 + c)
-1 + c = -1
c = -1 + 1
c = 0
2006-11-28 12:32:12 · answer #1 · answered by Kemmy 6 · 0⤊ 0⤋
cos (0) = 1 so c = 0.
2006-11-28 12:14:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
If you mean y(x) = -1/(-cos(x) + c), then
y(0) = -1/(-cos(0) +c).
But cos(0) = 1.
So, y(0) = -1/(-1 + c).
So, y(0) = 1 if and only if c = 0.
2006-11-28 12:13:57 · answer #3 · answered by oddy411 1 · 0⤊ 0⤋
put in values for y(0)=1
1=-1/(-1+c)
(-1+c)= -1
c=0
therefore,y= -1/(-cos x + c), y(0)=1
iff c=0
i hope that this helps
2006-11-28 21:23:33 · answer #4 · answered by Anonymous · 0⤊ 0⤋
i want to use my calcualtor but i lost my fingers yesterday!
wha! whaa!
: (
'
'
2006-11-28 12:50:29 · answer #5 · answered by Anonymous · 0⤊ 0⤋
penguin
2006-11-28 12:12:21 · answer #6 · answered by Anonymous · 0⤊ 0⤋