In a reaction between Iron II Chloride and Sodium Carbonate, which precipitate will form, Iron II Carbonate or Sodium Chloride. Both are naturally occuring minerals and my Chem teacher gave no guidelines on which forms. Can anyone help and possibly give guidelines on how to distinguish in the future?
2006-11-28 12:03:05 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Sodium chloride is table salt. It readily dissolves in water.
Iron (II) Carbonate, on the other-hand is not very soluble and will precipitate from the solution.
Sodium is an alkali metal (in the first column of the Periodic chart). Most simple alkali metal salts are soluble.
Check the site below for solubility rules of compounds. If you do not memorize this, at least print out a copy and keep it in your text or notebook.
2006-11-28 12:06:13 · answer #1 · answered by Richard 7 · 66⤊ 1⤋
the products would be sodium chloride this is soluble and iron carbonate which isn't soluble and could precipitate. Salts containing alkali metals mutually with sodium are consistently soluble with very few exceptions. Carbonates are oftentimes insoluble and featuring iron carbonate.
2016-12-29 15:33:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
These reactions are in solution, then, if there are precipitates. Remember these rules, they work in 99% for instances:
Alkali metals (Li, Na, K, etc) do not precipitate in solution.
Neither do ammonium (NH4 +) compounds, acetate compounds (C2H3O2 -), chlorates (ClO3 -), perchlorates (ClO4 -), and nitrates (NO3 -).
Oxides, hydroxides, carbonates, phosphates, sulfides, chromates, and dichromates always precipitate UNLESS they are with alkali metal or ammonium.
2006-11-28 12:13:45 · answer #3 · answered by doctorevil64 4 · 0⤊ 0⤋