i cant find the answer this problem is called factoring trinomials of the type ax^2 + bx + c and i need u to work it out and give me the rite answer
2006-11-28 11:13:35 · 5 answers · asked by Shante R 1 in Science & Mathematics ➔ Mathematics
x equals 2
2006-11-28 11:16:12 · answer #1 · answered by Anonymous · 0⤊ 4⤋
Posssibly you meant to write a leading parenthesis
(3x + 2)(3x + 4) = 18
9x^2 + 12x + 6x + 8 = 18
9x^2 + 18x - 10 = 0
This does not factor, but can be solved using the quadratic formula:
[-b +- sqrt(b^2 - 4ac)]/2a
2006-11-28 19:28:37 · answer #2 · answered by kindricko 7 · 0⤊ 0⤋
Multiply the parentheses first:
9x^2 + 18x + 8 = 18
Set = 0
9x^2 + 18x -10 = 0
This doesn't factor - are you using the quadratic formula yet? If so that is what you do next.
2006-11-28 19:21:04 · answer #3 · answered by MollyMAM 6 · 1⤊ 0⤋
9x^2+12x+6x+8
9x^2+18x+8
(3x+2)(3x+4)
2006-11-28 19:18:04 · answer #4 · answered by zlisa98 3 · 0⤊ 2⤋
3x^2=10 need to verify though (Im a little rusty)
2006-11-28 19:21:47 · answer #5 · answered by Antonio E 1 · 0⤊ 3⤋