Physics Question. How far will a box go if Initial Velocity is 3m/s and coefficient of kin. friction is .2?

Question

a box is given a push so that it slides across the floor. how far will it go, given that the coefficient of kinetic friction is .2 and hte push imparts an initial speed of 3.0 m/s

Thank you =]

Answer 1

The friction gives you Force F = kN = .2*m*g

That force causes acceleration a (in the negative direction) given by F = m*a. So a = .2*m*g/m
V^ = Vo^2 + 2*a*x where V=0 and Vo is given.

Answer 2

Frictional stress = uN u - coeff of friction N - conventional reaction of body = mass*acc.by way of grav = mg => F(fr) = uN = umg = 0.2 * 9.80 one * m => paintings performed (fr) = F * s = .2 * 9.80 one * m * s s - distance traveled Now, paintings performed = Kinetic skill = .5 m v^2 v - speed => KE = .5 * 16 * m Equating, paintings performed(fr) = KE => s= 4.077m (Ans)

Answer 3

0.5*M*V*V=M*G*0.2*L
0.5/0.2*9=9.8*L
L=(45/2)/9.8 (Meters)
L=2.25 (m)