At 88 mph.
2006-11-28 10:47:19 · 10 answers · asked by Aaron P 1 in Cars & Transportation ➔ Other - Cars & Transportation
In order to travel through time, the vehicle integrated with the flux capacitor needs to be travelling at 88 mph (141.6 km/h), and requires 1.21 gigawatts of power (1 210 000 000 watts), originally supplied by a plutonium-powered nuclear reactor. See the link below.
And, it is actually spelled gigawatt, but pronounced "jigawatt". See the other link below.
2006-11-28 11:14:23 · answer #1 · answered by Kevin P 3 · 0⤊ 0⤋
Do you know what a "Jacob's Ladder" circuit is? It is a circuit designed to multiply voltages. Depending on how robust the device is made will determine how much current it can handle. Therefore, with these two things in mind, to build a power supply capable of producing 1.21 giga-watts you will need to determine the total wattage capability. Now, assume you want to follow general engineering principals: Typically a factor of 1.3 to 1.5 over-design is common. I prefer to design to 1.5 X. So, if your need is 1.21 GW, your supply should be capable of 1.8 GW. That way you will not run into any unforeseen limiting factors. Now, the construction: To simplify construction, I'll assume you know how to build a "Jacob's Ladder" (JL for short). By adding a few active components, something like a J-K Flip/Flop chip should be able to help you build sufficient power levels. By momentarily powering the JL through the "J" circuit, allow the JL to run momentarily. (frequency will depend on discrete components) At any given frequency, clock the J-K so the output becomes the input and power it from the JL output. The added power will feed back into the JL causing an increase in power. Depending on what frequency and other minor factors, your JL power supply SHOULD be able to develop, in theory, well over 5 GW of power. One word of caution, when working with those kinds of voltages, be sure your flux capacitor has been properly cleaned of ALL possible contaminants, as these unforeseen dust particles can become conductive. At that level of power, a short could result in a plasma of hundreds of thousands of degrees. Quite literally, you are building a bomb. Assuming you've keept things clean down to class C-1 you should be good. One hint that a lot of people might overlook is to flush the flux capacitor with Argon gas. The inert gas will aid in preventing any sudden, spontaneous self destruction. Once you have your circuit powered and your capacitor charged, go back in time to when you were a little boy and convince yourself to pay more attention in school. I don't want to have to repeat this explanation again. Good luck. :)
2016-05-22 23:30:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋
ask the professor in back to the future.
2006-11-28 12:22:21 · answer #3 · answered by mister ss 7 · 0⤊ 0⤋
I think Mr. B is actually right.
2006-11-28 10:52:01 · answer #4 · answered by diamond_joe1979 3 · 0⤊ 0⤋
1.21 gigawatts!
2006-11-28 10:49:40 · answer #5 · answered by Mr B 2 · 2⤊ 0⤋
None..!!!!!
It runs on kinetic energy...
2006-11-28 12:17:02 · answer #6 · answered by Dr. AssWhole 4 · 0⤊ 0⤋
Ok you got me there!!! Sorry
2006-11-28 10:49:35 · answer #7 · answered by SWEETSTEPH 2 · 0⤊ 0⤋
jigawatts
2006-11-28 10:58:15 · answer #8 · answered by mr wabbit 5 · 0⤊ 0⤋
1.21
2006-11-28 10:55:49 · answer #9 · answered by Steve 2 · 0⤊ 0⤋
what the hell is jiggawatt?
2006-11-30 02:43:05 · answer #10 · answered by My Dog Rowdy 5 · 0⤊ 0⤋