a.) What it the probability that heads will occur exactly three of the four times?
b.) What are the odds for heads occuring exactly three times?
c.) What are the odds against heads occuring exactly three times?
I think i have the right answers, but i would like to see what someone else gets.....Someone answer ASAP!
2006-11-28 09:58:31 · 4 answers · asked by Nathan D 1 in Science & Mathematics ➔ Mathematics
a) There are 16 combinations and 4 of them include exactly 3 heads (HHHT, HHTH, HTHH, THHH). So the probability is 4/16 or 1/4.
b) This question results in the same probability (4/16 = 1/4), except it asks for it as 'odds' which is the probability of success divided by the probability of failure. That is 1 to 3 odds.
c) The odds against heads are just the reverse. Probability of failure divided by probability of success. That is 3 to 1 odds against.
2006-11-28 10:04:56 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
a) There is a 25% chance of heads (or tails) occuring exactly (only) three of the four times.
b) The odds are 1 in 4 that heads would occur exactly three times.
c) The odds are 3 in 4 against heads occuring exactly three times.
2006-11-28 18:07:05 · answer #2 · answered by sep_n 3 · 0⤊ 1⤋
a) The chances of HHHT is 0.5*0.5*0.5*0.5 = 1/16. However, there are 4 options for where the T goes, so multiply by 4 to get 1/4.
b,c) You have one chance in 4, so the odds would be 1:3 or 3:1 against.
2006-11-28 18:02:03 · answer #3 · answered by stephen m 4 · 0⤊ 0⤋
the odds for all three is 50/50
2006-11-28 18:07:09 · answer #4 · answered by deadzed 2 · 0⤊ 1⤋