factoring binomials and trinomials?

Question

can someone help me about factoring binomials and trinomials, or explain the rainbow method? any help at all would be great. examples would help too. my teacher is on dope so she didn't explain it too well and i don't even know how to start this assignment she gave today.

Answer 1

For a binomial:

Suppose you have a binomial,
Ax^2 + Bx + C = 0. You can factor this into (X - r1) * (X - r2). To find r1 and r2, you can use

r = (-B + (B^2 - 4AC)^.5) / 2 and (-B - (B^2 - 4AC)^.5) / 2

This will always work.

For example, suppose you have x^2 + x - 12 = 0. Then A=1, B=1, and C=-12. Using the formula I gave you,

r = (-1 + (1 + 49)^.5)/2 = (-1 + 7)/2 = 3, and
r = (-1 - (1 + 49)^.5)/2 = (-1 -7)/2 = -4, so you have (X-3)*(X+4).


I don't know what the rainbow method is.

Answer 2

Check this site out:
http://www.algebra-online.com/factoring-binomials-trinomials-1.htm
Hope it helps.

Answer 3

IN MULTIPLICATION: you're able to multiply the coefficients(quantity next to a variable) and upload the exponents. Ex: (2x+a million)(5x-6)^3 (2x+a million)(5x-6)(5x-6) FOIL any 2 (very last 2 for me) (2x+a million)(25x^2-60x+36) Distribute both the 2x and the absolutely million to 25x^2-60x+36 answer= 50x^3-95x^2+12x+36 besides: you're able to upload coefficients yet shop the exponents a similar!! Ex: (2x^3+6x^2)+(4x^3-4x^2)=6x^3+2x^2 (this is plenty a lot less complicated!)

Answer 4

I hope this helps, but I don't know the term "Rainbow method".

http://www.algebra-online.com/factoring-binomials-trinomials-1.htm

http://www.algebra-online.com/sum-difference-cubes-1.htm

http://www.gpc.edu/~jgutliph/Books/ia/review_ba/factoring_review.htm

http://library.thinkquest.org/20991/alg/factoring.html

http://home.xnet.com/~fidler/triton/math/review/mat110/factor/binom/binom.htm

http://www.education-world.com/a_curr/mnemonics/mnemonics033.shtml