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(8 -radical10)(5- radical10)

2006-11-28 08:59:39 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

That isn't an algebra 'problem'. Perhaps you were asked to expand it?
In which case, (8-√10)(5-√10) = 8*5 - 5√10 - 8√10 + √10*√10 = 40 - 13√10 + 10 = 50 - 13√10.

2006-11-28 09:02:51 · answer #1 · answered by stephen m 4 · 0 0

241 and 3/8

2006-11-28 17:01:31 · answer #2 · answered by Deonte 2 · 0 2

241 and 3/8 this is ur best answer !!!!!!!!!!!!!!!!!!!!!!!



Fat guy smiling =)))

2006-11-28 17:02:47 · answer #3 · answered by Chetan 2 · 0 1

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