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It fires a .150kg baseball at an angle of 30 degrees with the vertical at a speed of 20 m/s. What is the recoil velocity of the machine?

2006-11-28 08:15:43 · 1 answers · asked by Kayla H 1 in Science & Mathematics Physics

1 answers

the impuls (m*v) is conserved, so the impulse in one direction;
0.150*20*sin(30deg)
Equals the impulse in the other direction
50*v_recoil
the recoil velocity is thus 0.03 m/s

2006-11-28 08:29:13 · answer #1 · answered by Anonymous · 0 0

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