horizontal. If the crate moves at a constant speed, fing the coefficient of sliding friction between the crate and the floor.
2006-11-28 08:07:04 · 2 answers · asked by Kayla H 1 in Science & Mathematics ➔ Physics
If the crate isn't accelerating, then the sum of the forces in both the X and Y directions are 0. The forces in the X direction are the force of kinetic friction (negative) and the X portion of the 750N force (750 times the cosine of 30). The forces in the Y direction are the normal force, the Y portion of the 750N force (750 times the sine of 30), and the weight of the crate (negative 2000N). Since the sum of the Y forces are zero, we can say that N = mg - FsinT or 2000 - 375 = 1625N. Since the sum of the X forces are zero, the kinetic friction is equal to the X portion of the 750N force = 649.5N. The coefficient of kinetic friction is the friction force divided by the normal force (649.5N divided by 1625N), or approximately 0.4.
2006-11-28 13:27:31 · answer #1 · answered by scottr9 3 · 0⤊ 0⤋
a = [FcosΘ - µ(W - FsinΘ)]/(W/g) a = .64 m/s²
2016-03-28 23:04:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋