what's the answer for thses questions? note. look at the details for the qoestions?

Question

you have to solve inequalities by several trasformation

1. -6f+7<2f-9

2. 5/8g-4>2/3g+6

3. 5.4-10.9w

4. -2 1/9d+3/5<-3 2/9d-4 2/5

Answer 1

1.adding-2f-7
-6f-2f+7-7<2f-2f-9-7
-8f<-16
dividing by -8
x>2

2.5/8g-4>2/3g+6
adding 4
5/8g>2/3g+10
multiplying by 24
15g>16g+240
adding -16g
-g>240
dividing by -1
g<-240

3.sum incomplete

4.-2 1/9d+3/5<-3 2/9d-4 2/5
-19/9d+3/5<-29/9d-22/5
multiplying by45
-95d+27<-145d-198
adding 145d
50d+27<-198
adding -27
50d<-225
dividng by 50
d<-5 1/2

Answer 2

a) -6f +7 < 2f -9
-6f < 2f -16
-3f< f- 8
-4f < -8
4f>8
f>2
ex : f =3, -6f +7 < 2f -9 == -11< -3 , which is true.
b) 5/8g - 4 > 2/3g + 6
5/8g > 2/3g + 10
multiply by 24 on both sides
15g>16g +240
-g >240
g< -240
example...g = -264, 5/8g - 4 > 2/3g + 6 == -169 >-170,which is true.
c)???
d) -2 1/9 d + 3/5 < 3 2/9d - 4 2/5
-19/9 d + 3/5 < 29/9 d - 11/5
multiply throughout by 45
-95 d +27 < 145 d - 99
126< 240 d
21<40 d
21/40

Answer 3

1.

-6f+7<2f-9
-6f-2f<-9-7
-8f<-16
f>2

2.

5/8g-4>2/3g+6 (assuming g is in the denominator)

multiply through by 24g

15-96g>12+144g
15-12>240g
3>240g
1/80>g

5/8g-4>2/3g+6 (assuming g is not in the denominator - (5/8)g)

Multiply through by 24

15g-96>16g+144
-240>g

3.

Not complete

4.

Similar to 2.