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given: the bike is moving at 55 ft per second, the tires have a diameter of 30 inches

2006-11-28 06:22:51 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

perimeter of wheel= 2*pie*15 /12feet

bike moves 55ft per second so distance mov ed by bike in 1 minutes = 55*60

so number of revolution made by wheel in one minutes = 12*55*60/(2*pie*15)
=420.36 rpm

wheel makes 420.36 revolution per second

2006-11-28 06:30:14 · answer #1 · answered by vivek 2 · 0 1

The bike is moving 55 feet per second, and the tires have a diameter of 30 inches.

The first thing that I would do is find the circumfrence of the tires. Since we know the diameter is 30 inches, we know that the radius is 15 inches.
c = (π)(d) = (2)(π)(r) --- where c is circumfrence, (π) is the constant "pi", d is the diameter, and r is the radius.
π ≈ 3.141592654 --- For our purpose, we will use 3.14 for pi...
c = (π)(d)
c = (3.14)(30)
c = 94.2 inches

We know that the bike is going 55 feet per second. Since there are 60 seconds in 1 minute, we can say that bike is moving at:
(55)(60) = 3,300 feet per minute.
Now if we convert our circumfrence from inches to feet, we get:
94.2 inches / x feet = 12 inches / 1 foot
12x = 94.2 --- Divide both sides by 12...
x = 7.85 feet

Now, summarizing what we know now:
The circumfrence of the wheels is 7.85 feet.
The bike is moving at 3,300 feet per minute.

Therefore, revolutions per minute can be found by dividing 3,300 by 7.85:
3,300 / 7.85 ≈ 420.38

Answer: The wheels are turning at (approximately) 420.38 revolutions per minute.

2006-11-28 14:56:35 · answer #2 · answered by Anonymous · 0 0

The circumference of a circle is given by the formula:
C = pi * d

You have a given diameter of 30 inches or 2.5 feet.
C = 2.5 pi
C ≈ 7.85 ft / revolution

So each revolution is 7.85 ft. and you go 3,300 feet per minute.(55 ft/sec * 60 seconds/min = 3,300 ft/min)

If you divide the total distance (3,300 ft) by the number of feet per revolution (7.85 ft) you'll get the number of revolutions per minute.

Dividing:
3,300 / 7.85 ft. ≈ 420 rpm

2006-11-28 14:42:15 · answer #3 · answered by Puzzling 7 · 0 0

55/22/7*30/12
55*7*12/22*30
=7 revolutions/sec
=420 rpm

2006-11-28 14:33:57 · answer #4 · answered by raj 7 · 0 0

calculate the length of the wheel based on the diameter then you will now how many wheels/minute the bike is going

2006-11-28 14:28:40 · answer #5 · answered by Tiguerón 1 · 0 0

C = pi(30)
f = v/C = [55 ft/s]/[pi(30 in)/(12 in/ft)](60 s/min) ~= 420 rpm

2006-11-28 14:29:17 · answer #6 · answered by jacinablackbox 4 · 0 0

The tires' circumference is pi*diameter = 94.25 inches. That's how far one revolution takes you.

You can take it from there...

2006-11-28 14:26:58 · answer #7 · answered by Anonymous · 1 0

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