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(a) V=(P+w^2) / L

(b) If V=8, L=2, P=10 and G=0.35, find w.

please show working

2006-11-28 06:08:13 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

Your would make your teacher much happier, were you able to handle simple rearrangement of terms in an equation. You can easily do it by pattern recognition; that 's all that mathematics is.

(a) Start from V=(P+w^2) / L

Then LV = P + w^2

So w^2 = LV - P, i.e. w = (LV - P)^(1/2)

(b) Gee! There IS no G in your formula! So it's either irrelevant or you made a transcription error.

In any case, substituting the given values, the G-less w = (2x8 - 10)^(1/2) = 6^(1/2), or sqrt(6).

If you WERE given a G in the original formula, trace its effect for yourself and evaluate the consequence appropriately.

Live long and prosper.

2006-11-28 06:21:48 · answer #1 · answered by Dr Spock 6 · 0 0

(a) V = (P+w^2) / L
V*L = P + w^2
V*L - P = w^2
(V*L - P)^0.5 = w -- "^0.5" means it's the square root of the equation
what's with the G ? there is no G in the equation

(b) (8*2 - 10)^0.5 = w
(16-10)^0.5 = w
6^0.5 = w

2006-11-28 06:14:06 · answer #2 · answered by Triathlete88 4 · 0 0

(a) multiply the equation by L ---> LV = P+w^2 --> w^2 = LV-P

w = (LV-P) ^0.5 or w = square root of(LV-P)

(b)I do not understand where theG comes from?

w^2= 2*8 -10 = 6 w=2.45

2006-11-28 06:16:32 · answer #3 · answered by maussy 7 · 0 0

multiply L from both sides
VL=P+w^2
subtract P from both sides
VL-P=w^2
take a square root from both sides
w=sqr(VL-P)

w=sqr(8(2)-10)
w=sqr(6)

i dont know where G comes from

2006-11-28 06:12:57 · answer #4 · answered by      7 · 0 0

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