Pat has $3.20 in quarters, dimes and nickels. shehas the same number of each kind of coin. Find the Number of each kind of coin Pat has Solve algebraically
please show working
2006-11-28 06:04:53 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Let n be the number of each coin (she has the same number of each coin). Let's simplify things and do everything in cents (rather than dollars).
The value of the quarters would be 25n
The value of the dimes would be 10n
The value of the nickels would be 5n
All together she has 320 cents ($3.20).
Putting this into an equation:
25n + 10n + 5n = 320
Add the like terms:
40n = 320
Divide both sides by 40:
n = 8
Therefore Pat has 8 of each coin.
Her $3.20 is broken down as follows:
8 quarters = $2.00
8 dimes = $0.80
8 nickels = $0.40
2006-11-28 06:07:31 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋