f(1) = 4989484820458683 = 90
f(2) = 9894848204586834 = 90
f(3) = 8475408807538689 = 90
f(4) = 4494704956584678 = 90
f(5) = ? = 90
It is not just random numbers!
2006-11-28 05:36:42 · 6 answers · asked by slayersirus 1 in Science & Mathematics ➔ Mathematics
Look at the decimal expansion of phi (the golden ratio) and you'll have your answer...
Ф = 1.618033988749894...
1, 6, 1, 8, 0, 3, 3, 9, 8, 8, 7, 4, 9, 8, 9, 4, 8, 4, 8, 2, 0, 4, 5, 8, 6, 8, 3, 4, 3, 6, 5, 6, 3, 8, 1, 1, 7, 7, 2, 0, 3, 0, 9, 1, 7, 9, 8, 0, 5, 7, 6, 2, 8, 6, 2, 1, 3, 5, 4, 4, 8, 6, 2, 2, 7, 0, 5, 2, 6, 0, 4, 6, 2, 8, 1, 8, 9, 0, 2, 4, 4, 9, 7, 0, 7, 2, 0, 7, 2, 0, 4, 1, 8, 9, 3, 9, 1, 1, 3, 7, 4, 8, 4, 7, 5...
Look through until you find 16 consecutive digits that add up to 90.
The first set is 4989484820458683 = 90
The next set is 9894848204586834 = 90
The third set is 8475408807538689 = 90
The fourth set is 4494704956584678 = 90
Looking at the expansion I figured out the fifth set:
The fifth set is 5884607499887124 = 90
2006-11-28 05:47:05 · answer #1 · answered by Puzzling 7 · 2⤊ 0⤋
The only thing I noticed was that f(2) is f(1) with all of the digits shifted to the left 1 place, and 4 went to the back and the sum of all the individual digits in any one value is 90. I think.
I thought maybe it was a pattern, but the other numbers are completely random to me.
2006-11-28 05:46:41 · answer #2 · answered by Aegor R 4 · 0⤊ 0⤋
This does not make sense...f(5) can not = that really long number which equals 90. It doesn't make sense. What is the 90 there for?
2006-11-28 05:44:16 · answer #3 · answered by chrisjptine 1 · 0⤊ 0⤋
well, the digits of the long numbers add up to 90, but how does that help me find f(5)?
2006-11-28 05:45:53 · answer #4 · answered by pito16places 3 · 0⤊ 0⤋
What Class/Grade Level is this for?
2006-11-28 05:41:20 · answer #5 · answered by Kirk H 2 · 0⤊ 0⤋
non sense
2006-11-28 05:45:42 · answer #6 · answered by Tiguerón 1 · 0⤊ 0⤋