A rotating rod that is 15.3 cm long is spun with its axis through one end of the rod so that the other end of the rod has a speed of 2000 m/s (4,500 mph).
a. What is the centripetal acceleration of the other end of the rod?
b. If you were to attach a 1.0-g object to the end of the rod, what force would be needed to hold it on the rod?
Please help me with this problem.
I'm having a hard time understanding it.
2006-11-28 04:57:31 · 3 answers · asked by swimmertommy 1 in Science & Mathematics ➔ Physics
the rod will spin the same
2006-12-01 20:09:56 · answer #1 · answered by rocketman 3 · 0⤊ 1⤋
imagine the rod is nailed to point on one end. the other end is allowed to spin around the nail. thus the spinning rod carves a circle of radius 15.3cm or 0.153m.
to find centripetal acceleration, its a=v²/r, or 2000²÷0.153=26.1 million m/s².
to find centripetal force, its F=ma, or 26.1million × 0.001kg=261kN
this is the centripetal force acting on the object. so the force required to hold it in place is also 261kN.
2006-11-28 05:33:35 · answer #2 · answered by Anonymous · 1⤊ 0⤋
The 7.00m is the radius. 8.0 N is mass, and additionally you will might desire to instruct 220 rev/min to rad/s.and in keeping with possibility 8N into Kg. once you are trying this particularly adventure the factors you have (radius, mass, angular velocity) and adventure them with a formulation out of your e book.
2016-12-13 15:59:22 · answer #3 · answered by ? 4 · 0⤊ 0⤋