Can anyone assist me?

Question

MATH HELP PLEASE............
1.)Find the equation in the y = mx + b form of the line that contains the point (3,2) and has a slope of 4/3.

2.)The slope of the line 3y = x - 3 is

Answer 1

We can use the point-slope form of the equation and then transform it into the slope-intercept form.

(y - y1) = m(x - x1)
(y - 2) = 4/3(x - 3)
y - 2 = (4/3)x - 4
y =(4/3)x - 2.

m = 4/3, b = -2

3y = x - 3
y = (1/3)x - 1

The slope m = 1/3

Answer 2

Use the equation that you have been given.

Y is the second number in the coordinate pair and x is the first
(x,y). m= the slope of the line and b= the point where the line crosses the y axis.

y=4/3(x) + ?. if you plug in 3 for x and amd 2 for y then you get 2=4/3(3) +?. continuing you get 2=4+? becase 4/3 times three equals 4. What number do you add to four to get two? why -2 of course (read as negative 2). so the actual equation is y=4/3(x) - 2.

for number 2, The equation is in the form y=mx+b. that means the coefficient of x is the slope. This is always true for an equation that is in this form. When there is no number there the coefficient is presumed to be 1. So the slope of the line is 1.

Have a good time.

Answer 3

1) You must find the y-intercept, or "b" of your equation. To do this, you must have the slope and a point on the line. Because you have both, we can plug them into formula and solve for "b".

y = 4/3*x+b at (3,2)
2 = 4/3*3 + b
2 = 4 + b
2 - 4 = b
b = -2

Therefore the line is: y = 4/3*x - 2

2) To find the slope, we first must solve for y.

3y = x - 3
y = 1/3*x - 1

By comparing this to the y = mx + b formula, we see that the slope of the line is 1/3 and the y-intercept is at (0,-1)

Answer 4

1. y = (4/3)x + b m=slope
2 = (4/3) 3 + b substitute 3 for x, 2 for y, then solve for b
2 = 4 + b
-2 = b

y = (4/3)x -2 now plug in what you know into the equation format


2. put this equation into the y=mx+b form

3y = x - 3
y = (x -3) /3
y = x/3 - 1 or y = (1/3)x -1

the slope is 1/3

Answer 5

1. The formula for point-slope is y - y1 = m(x - x1), where m is the slope, x1 is the x-coordinate of the point, and y1 is the y- of the point; x and y are variables. To get slope-intercept form, or y=mx+b, just solve for y and simplify.
2. Again, convert to slope-intercept form by solving for y and simplifying.

Answer 6

1.y-2=(4/3(x-3)
multiplying by 3
3y-6=4x-12
adding 6
3y=4x-6
dividing by 3
y=(4/3)x-2

2.slope=1/3

Answer 7

pt1 (3,2)

(Y-y1) = M(X-x1)
Y-3 = (4/3) (X-2)
Y-3 = 4/3X - 8/3
Y (-9/3) = 4/3X -8/3 + 9/3

Y = 4/3X + 1/3


3y = X - 3
(1/3) 3Y = (1/3) X - (1/3)3

Y = 1/3 X - 1 ......... m= 1/3

Answer 8

(3,2) = (x,y)
m = 4/3

b = y - mx
b = 2 - ((4/3)*3)
b = 2 - 4
b = -2

Equation: y = (4/3)x -2