An airplane is flying near a football stadium at 12000 feet above level ground. The angle of depression from the airplane to the stadium is 13 degrees. How far horizontally must the plane fly to be directly over the football stadium? Round answer to nearest thousand feet.
2006-11-28 04:19:34 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Yes, x= (12000)/tan(13) = about 52000ft
2006-11-28 04:27:02 · answer #1 · answered by Stu 2 · 0⤊ 0⤋
Yes, you did it right. Basic equation is h/d = tan 13°, so d = 12000/tan 13 = 51,978.
2006-11-28 04:28:32 · answer #2 · answered by Philo 7 · 0⤊ 0⤋
We have the angle, the opposite side, and want the adjacent side. Clearly we want to use the tangent. Thus, tan (13 deg) = 12,000/x.
Solving for x, I got 51977.71049..., or about 52 thousand, feet.
Good job.
2006-11-28 04:25:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋
12000 is height .... 13 degrees down is the football field ....
distance to the field is ....tan(13) = (12000 / X)
X = 12000 / (tan(13)) = 51,977 '
good !!
2006-11-28 04:30:24 · answer #4 · answered by Brian D 5 · 0⤊ 0⤋
Yes
2006-11-28 04:24:07 · answer #5 · answered by Anonymous · 0⤊ 0⤋