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What is the pH of a solution that has [H3O^+]=6.0*10^-3 M?

2006-11-28 03:59:04 · 2 answers · asked by carmond70 1 in Science & Mathematics Chemistry

2 answers

pH=-log[H30+]
pH =-log(6.0*10^-3)
pH =-(-2.2)
pH = 2.2

2006-11-28 04:05:08 · answer #1 · answered by Peter B 3 · 0 0

pH = -log(6*10^(-3)), pH = 3 - log6, pH = 3 - 0.78, so:

pH = 2.22

2006-11-28 04:03:49 · answer #2 · answered by Dimos F 4 · 0 0

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