y= -2/3x + 1
y= -2/3x - 4
The question is whether its Parallel, Perpendicular, or neither.??
2006-11-28 03:47:24 · 5 answers · asked by crazybrunette1991 2 in Science & Mathematics ➔ Mathematics
Both equations are in slope-intercept form (y = mx + b).
In your case, both lines have the same slope (-2/3) but different y-intercepts (+1 for the first, -4 for the second). Lines with the same slope but different y-intercepts are PARALLEL.
(Note: if you got slopes that were the same and the intercepts were the same, the lines would be coincident -- the same line. If the slopes were negative inverses, e.g. 2/3 and -3/2, then they would be perpendicular. And if the slopes were completely different the lines would be skew.)
2006-11-28 03:55:47 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋
Im in 9th class and I got the correct answer for you.....These are 2 simultaneous equations that you have to solve graphically on a graph paper (that has a specific method if you know it)and then see the 2 lines if they are parallel,perpendicular or connected or whatever.(so simple damn)
2006-11-28 04:35:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Parallel as the gradients are the same.
In the case of Perpinducular the gradients would have had a product of -1.
2006-11-28 03:54:37 · answer #3 · answered by Wayfarer 1 · 0⤊ 0⤋
the lines are parallel as the slopes are the same
2006-11-28 03:49:08 · answer #4 · answered by raj 7 · 0⤊ 0⤋
Duh?
2006-11-28 03:48:26 · answer #5 · answered by Anonymous · 0⤊ 1⤋