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What is the correct "expression" for the equilibrium constant Keq for this reaction? N2(g) + 3H2(g)<------>2NH3(g)

2006-11-28 03:38:33 · 2 answers · asked by carmond70 1 in Science & Mathematics Mathematics

2 answers

it's products over reactants, so that's Keq = NH3 squared / (N2)(H2) ...the H2 is to the third power, i don't know how to type that on here.

2006-11-28 03:41:51 · answer #1 · answered by jason e 2 · 0 0

k=[NH3]^2/[N2][H2]^3

2006-11-28 11:47:56 · answer #2 · answered by raj 7 · 0 0

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