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it might sound like a dumb Q, but its my final lab of the year, and i don't want to make any mistakes, so i have to make sure,
please don't answer nonsense for the points, bcause it will be reported as abuse.

2006-11-28 03:34:33 · 4 answers · asked by matin_10_ 2 in Science & Mathematics Biology

4 answers

Well, H202 would be the substrate....and I forget what enzyme degrades H2O2........its in the peroxisome i think...

2006-11-28 03:41:13 · answer #1 · answered by anon 4 · 0 0

Hydrogen peroxide, or H2O2, is the substrate. The enzyme that is added is called Catalase. Like any other enzyme, Catalase performs better at a certain pH, concentration, temperature, etc.

You know that Catalase is what causes the reaction because when you add H202 and sand, the sand acts as the negative control. When you add the H2o2 and MnO2 (which is an inorganic catalyst that simulates catalase), the MnO2 acts as the positive control.

The reaction that happens is that Catalase breaks down the H2O2 into O2 + 2H20, which means that it the reaction turns H2O2 into oxygen and water.

2006-11-28 04:28:37 · answer #2 · answered by Izzybear123 2 · 0 0

That is a silly question, however, the liver is full of enzymes to break down drugs (such as the cytochrome p450's) and digest lipids from lacteal. It is also impossible for H2O2 (hydrogen peroxide) do be an enzyme. Therefore, H2O2 would definetly be the substrate, while the liver would be the enzyme.

2006-11-28 03:38:49 · answer #3 · answered by jason e 2 · 0 0

H2O2 is the substrate, liver contains enzyme called catalase that can degrade peroxide to H2O and O2.

2006-11-28 04:02:36 · answer #4 · answered by chiman 3 · 0 0

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