The line 3x + 4y - 6 = 0 crosses the x-axis at x =
2006-11-28 02:49:07 · 6 answers · asked by Dianna 4 in Science & Mathematics ➔ Mathematics
ok so take the y out, so then the problem will be 3x-6=0, then put the -six over to where the 0 is, so now its 3x=6 so just solve for x, and its x=2
2006-11-28 03:23:25 · answer #1 · answered by Joseph C 1 · 1⤊ 0⤋
Since you want to know the value of 'x' when the line 3x + 4y - 6 = 0 passes the x-axis, eliminate y by taking its value as 0
y = 0
3x + 4(0) - 6 = 0
3x - 6 = 0
3x = 6
x = 6/3
x = 2
The line crosses the x-axis at x = 2
2006-11-28 11:01:57 · answer #2 · answered by Akilesh - Internet Undertaker 7 · 1⤊ 0⤋
Set y equal to zero and solve for x.
3x + 4(0) - 6 = 0
add six to both sides
3x = 6
divide both sides by 3
x = 2
so, it crosses the x-axis at x=2
2006-11-28 10:59:17 · answer #3 · answered by Erik A 1 · 1⤊ 0⤋
you mean at Y=, right? when X=0 Y=1.5 (x axis)
when Y=0 X=2 (y axis)
2006-11-28 10:52:44 · answer #4 · answered by pito16places 3 · 1⤊ 0⤋
At x axis y co ordinate = 0
3x-6=0
x= 2 Ans.
2006-11-28 10:59:48 · answer #5 · answered by aminnyus 2 · 1⤊ 0⤋
y is zero cuz there is no y value given
3x-6=0
add 6 to both sides
3x=6
divide 3 by each side
x = 2
2006-11-28 11:30:14 · answer #6 · answered by unan1m0us 5 · 1⤊ 0⤋