You have a 25%w/v solution of citric acid (molecular weight 192.1). What molarity is this?

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You have a 25%w/v solution of citric acid (molecular weight 192.1). What molarity is this?

2006-11-28 00:16:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

4 answers

Molarity of the solution = Number of moles of citric acid /1000 ml of solution

= (250/192.1) moles of citric acid per 1000 ml of solution

= 1.3014 M

2006-11-28 00:36:45 · answer #1 · answered by SB 1 · 0⤊ 0⤋

this means 250g/l of citric acid

molarity = 250/192.1 =1.3 M

2006-11-28 00:39:10 · answer #2 · answered by maussy 7 · 0⤊ 0⤋

Citric acid = H2C-C-COOH It demands 3 moles of NaOH to neutralize a million mole citric acid I CO--C-COOH I H2C-C-COOH Moles of NaOH= 0.121 x 0.01573L = 0.002836 Moles of acid neutralized = 9.454x10^-4 moles / 0.02573L =0.06010 M

2016-12-10 17:38:20 · answer #3 · answered by Anonymous · 0⤊ 0⤋

1.3 molar

2006-11-28 00:39:05 · answer #4 · answered by abdo 1 · 0⤊ 0⤋