[Math Problem] What are the numbers?!?

Question

one number is twice another. When the larger number is decreased by 10 the result is 2 greater than the smaller number. What are the numbers. ^_^ help please...

2x 1st number/ larger number
2x-10= [2 numbers higher than the value of the smaller number]

Answer 1

Let x = "one number".
Then, the "another number" is 2x.

When the larger number is decreased by 10,

2x - 10

The result is 2 greater than the smaller number

x + 2

Therefore,

2x - 10 = x + 2, and
x = 12.

So the two numbers are x and 2x, or 12 and 24.

Let's put it back into the problem.

One number is twice another. 24 is twice 12.
When the larger number is decreased by 10 (24 - 10 = 14), the result is 2 greater than the smaller number (2+12 = 14). Therefore that's the answer!

Happy solving!

Answer 2

The numbers are 24 and 12.

Solution: (let one number be x and the other y.
x = 2y (one number is twice another)
x - 10 = y + 2 ( the larger number is decreased by 10
is 2 greater that the smaller number, so add two)
subtract both sides gives

x - (x-10) = 2y - (y+2)
x - x +10 = 2y - y - 2
10 = y -2
12 = y

then x = 2y = 2*12
x = 24

Answer 3

Let two numbers be a and b
By your observations
a = 2b and a - 10 = b + 2 [thus a is larger number]
Substituting a = 2b in a - 10 = b + 2, we get
2b - 10 = b + 2
=>2b - b = 2 + 10
=>b = 12
And a=2b => a = 2*12 = 24
Thus, two numbers are a=24 and b=12.

All the bset

Answer 4

Let the numbers be 'x' and '2x'
2x - 10 = x + 2
2x = x + 2 + 10
2x = x + 12
2x - x = 12
x = 12
2x = 2*12 = 24

The numbers are 12 and 24.

Answer 5

10 to the second power or divide the 2 and the 10.

Answer 6

first num is x
the 2nd num is y

x=2y.......1
x must be bigger than y (look at the equation), so..
x-10=2+y.....2

substitute 1 -> 2
2y-10=2+y
2y-y=2+10
y=12
x=24

the nums are 24 and 12

Answer 7

12 and 24

6:12
6: 2
12:24
12:14

Answer 8

x = 12
y = 24