1. 15p^2q / 48pq = 5pq/ 16q
2. x-x^4 / x+x^3 = -x (x^3-1) / x (x^2+1)
3. 15+x-6x^2 / 6x^2-19x+15 = (2x+3) / 2x-3)
4. 14x^2y / 4xy^2 = 7xy / 2y^2
2006-11-27 21:40:11 · 4 answers · asked by avenger 2 in Science & Mathematics ➔ Mathematics
1) yes
2) get rid of x factor, so -(x^3-1)/(x^2+1)
3) You lost a negative, (2x+3)/(3-2x)
4) Remove y factor: 7x/2y
Steve
2006-11-27 21:46:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1. 15p^2q / 48pq = 5pq/ 16q = 5p/16
2. x-x^4 / x+x^3 = -x (x^3-1) / x (x^2+1) = -(x^3-1)/(x^2+1)
3. 15+x-6x^2 / 6x^2-19x+15 = (2x+3) / 2x-3)
4. 14x^2y / 4xy^2 = 7xy / 2y^2 = 7x / 2y
2006-11-27 22:37:15 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
Yes
2006-11-27 21:46:19 · answer #3 · answered by AndyPandy 3 · 0⤊ 0⤋
1. 5p/16, q cancels out in num and denom
2006-11-27 22:20:01 · answer #4 · answered by anami 3 · 0⤊ 0⤋