The standardization of NaOH(aq) using potassium hydrogen phthalate (abbreviated KHP, molar mass 204.22 g/mol,
The titration of acetic acid(aq) with the standardized NaOH(aq).
You will dissolve 0.30 g of KHP in 20 mL of water and titrate with the NaOH. To the nearest mL, calculate the volume of NaOH expected assuming that the NaOH concentration is ~0.1 M.
2006-11-27 19:25:57 · 2 answers · asked by smile 1 in Science & Mathematics ➔ Chemistry
The stoichiometry of the titration is 1:1 therefore
mole acid=mole base
but mole acid =mass/MW
and mole base=Cb*Vb
Thus
mass/MW=Cb*Vb => Vb=mass/(MW*Cb)= 0.3/(204.22*0.1) = 0.01469L =14.69 mL= 15 mL
Be careful with the units...
2006-11-27 23:10:15 · answer #1 · answered by bellerophon 6 · 0⤊ 0⤋
if nobody answers this, email... dont have the time now
2006-11-28 03:32:00 · answer #2 · answered by Sid Has 3 · 0⤊ 0⤋