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Solve the equation...
3 log x = 4 log 27

x = ...?

2006-11-27 17:39:49 · 4 answers · asked by OO 1 in Science & Mathematics Mathematics

4 answers

3 log x = 4 log 27
log x^3 = log 27^4
x^3 = 27^4
(x^3)^(1/3) = (27^4)^(1/3)
x = 27^(4/3)
x = 3^4
x = 81

2006-11-27 17:55:40 · answer #1 · answered by csp 2 · 0 0

log x = 4/3 log 27
convert to exponential

x = (27) ^4/3 = 81

without calculator

27 = 3 ^3 and (3^3) ^4/3 = 3^4 = 81

2006-11-28 01:56:41 · answer #2 · answered by maussy 7 · 0 0

3 Log x = 4 Log 27 therefore Log x^3 + Log 27^4 therefore x^3 = 27^4 = 3^7 therefore x = 3^4 = 81. QED

2006-11-28 01:46:57 · answer #3 · answered by Scythian1950 7 · 0 0

x^3=27^4
x=81

2006-11-28 01:44:17 · answer #4 · answered by KT 2 · 0 0

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