3(z+2) = 5z +6?

Question

Need a little nudge here. I cancel out the sixes and then what?

Answer 1

3z+6 = 5z+6
3z = 5z
3z-5z=0
-2z=0
z=0

plug it back in to double check
and it does... 6=6

Answer 2

If 3(z+2)=5z+6 then,
3z+6=5z+6 so,
5z-3z=6-6 hence
2z=0 thus
z=0

Answer 3

3(z+2) = 5z + 6

sol'n
3(z+2) = 5z+6
3z+6 = 5z+6
3z-5z = 6-6
-2z = 0
-2z/-2 = 0/-2
z=0

CHECKING:


3(0+2) = 5(0)+6
3(2) = 0+6
6 = 6

1. USE DISTRIBUTIVE PROPERTY OF MULTIPLICATION
2. COMBINE SIMILAR TERMS THEN SOLVE
3. DIVIDE BOTH SIDES OF THE EQUATION BY -2 TO CANCEL OUT THE NUMERICAL COEFFICIENT AND TO GET THE VALUE OF THE UNKNOWN, WHICH IS Z

note: if you will transfer a term from one side of the equation to another side then dont forget to change its sign.
if it is (+) then change it to (-) or otherwise, from (-) to (+)

Answer 4

You can't cancel the 6s:

3(z+2)=5z+6[multiply so that you can remove the brackets]
= 3z+6=5z+6
3z-5z=6-6[bring the variables to one side and constant to other side][don't forget to change the sign]
-2z=-0
z=-2\0
=-2

hope you understood

Answer 5

3(z+2)=5z+6, distribute the 3
3z + 6 = 5z + 6, subtract 6 from both sides
3z = 5z + 0, subtract 5z from both sides
-2z = 0, divide both sides by -2
z = 0.
Check by plugging 0 in for z in original problem...

3(0+2)=5(0)+6
3(2)=0+6
6=6, it checks out, so the answer is z = 0

Answer 6

3(z + 2) = 5z + 6 distribute

3z + 6 = 5z + 6 get variables and numbers on opposite sides
-3z - 6 = -3z - 6

0 = 2z divide by 2

z= 0

Answer 7

3(z+2) = 5z +6 distribute 3
3z+6=5z+6 subtract 6 from both sides
3z=5z subtract 3z from each side
2z=0 divide by 2
z=0

Answer 8

After you cancel out the 6's you are left with

3z = 5z

If you were to divide both sides by z, you would be left with
3 = 5, which obviously can't be true.

So 3z = 5z means z = 0.

Answer 9

It just doesn't work out. Oh wiat yes it does. Then when you cancel out the sixes you have 3z = 5z. Now that you see that you subtract 3z from both sides to get: 0 = 2z. Now you see that you have to find "what" times 2 equals 0. 0!

Answer 10

3(z + 2 = 5z + 6

3z + 6 = 5z + 6

3z + 6 - 3z = 5x + 6 - 3z

6 = 2z + 6

6 - 6 = 2z + 6 - 6

0 = 2z

0/2 = 2z/2

0/2 = z

0 = z

The answer is z = 0

Insert the z value into the equation

- - - - - - - - - - - - - - - - - - - - - - -

Check

3(z + 2) = 5z + 6

3(0 + 2) = 5(0)+ 6

3(2) = 0 + 6

6 = 6

- - - - - - s-

Answer 11

No solution

3(z+2)=5z+6
3z+6=5z+6
3z=5z
z=(5z/3)
(z/z)=(5/3)
1=(5/3)
= No Solution