The ideal surface area of a rubber ball shipped from the factory is 50.25 sq in..?

Question

The company inspector insists that the balls shipped vary no more than 0.3 sq in of this total. To the nearest hundredth, what is the minimum and the maximum value for the surface area of rubber balls shipped?

Minimum answers:
50.25
49.95
50.55
none

Maximum answers:
50.25
49.95
50.55
none

Answer 1

If you subtract the 0.3 sq. inches you will get the minimum.
50.25 - 0.30 = 49.95 sq. inches

And if you add the 0.3 sq. inches you will get the maximum.
50.25 + 0.30 = 50.55 sq. inches

Answer 2

You need to derive the equation for the SA of a sphere. your dr= +-0.3 sq.in.

Once you've derived your Surface Area function, find your radius and plug in the positive 'dr' value for max and negative 'dr' value for min. Check using a number line (set SA' equal to zero) and evaluate your solution on either side to determine max or min.

Answer 3

mininmum 49.95 to maximum 50.55