skelton equation for copper chloride and lead nitride?

Question

write a skelton equation with the corrected formula for each chemical in the reaction.

Answer 1

This is difficult, as there may be more than one formula for the compounds you listed.

Copper (I) chloride is CuCl
Copper (II) chloride is CuCl2
Lead nitride is usually used to mean "yellow lead" which is Lead (II) nitride, which is Pb3N2;
but it could also be used for Lead (IV) nitride which is Pb3N4.

One possible reaction:
Pb3N2 + 3 CuCl2 --> Cu3N2 + 3 PbCl2

This is a double replacement with no redox.

Answer 2

This is a single displacement reaction. A + BX → AX + B. Aluminum metal has a +3 charge, Copper (II) has a +2 charge, and Chlorine has a -1 charge. Make sure the charges cancel eachother out. Example:CuCl2: Copper (II) which has a +2 charge and 2 Chlorine each with a -1 charge. Make sure the equation is balanced as well. So it would be: 3CuCl2 + 2Al ---> 2AlCl3 + 3Cu Each side of the reaction has 3 copper (II), 6 chlorines, and 2 aluminums.