K this is the problem
The sum of two numbers is 75. The first is 9 more than 5 times the second. Find the first number
I got:
(5x+9)+x=75
6x+9=75
6x = 66
x=11
Whats wrong with it?!??!?
2006-11-27 14:57:35 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
let the first number be x and second be y
x= 9+5y
you are also given that x+y =75 ...from here you know that y=75-x
substitute this into the previous equation and you get:
x= 9 +5(75-x)
x= 9 + 375 - 5x
6x=384
x= 64
so ur numbers are 64 and 11
64 is 9 more than 5 times 11...means 64 is 9 more than 55...which is true
so you almost got it! Great job!
2006-11-27 15:04:10 · answer #1 · answered by xcessive_assassin 1 · 0⤊ 0⤋
Here we go
1st #=x
2nd#=5x+9
5x + 9 + x = 75
6x+9=75
-9 -9
6x=66
x=11 therefore (5 x11+9) + 11 = 75
(55+9) +11 = 75
75 =75
1st # = 11
2nd # = 64
hope i helped
italianpride127
2006-11-27 23:08:08 · answer #2 · answered by italianpride127 2 · 0⤊ 0⤋
Your first number is 5x+9
Your second number is x
You set up your equation correctly. You figured out that the second number was 11.
All you have to do now is plug 11 back into 5x + 9.
5(11) + 9 = 55 + 9
64 is the first number.
You actually did very good (just missed the last step).
2006-11-27 23:09:08 · answer #3 · answered by Math Helper 3 · 0⤊ 0⤋
It's ok, it's just that they ask you to find the first number so what you have to do is multiply 11 per 5 and add 9, like this
11*5+9 = 64
hope this helps
2006-11-27 23:11:02 · answer #4 · answered by mensajeroscuro 4 · 0⤊ 0⤋
there is nothing wrong with it.
2006-11-27 23:01:11 · answer #5 · answered by Russianator 5 · 0⤊ 0⤋