2006-11-27 14:40:08 · 16 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Solve
3y=-12
y=-4
2006-11-27 14:47:35 · answer #1 · answered by af12af3af 2 · 0⤊ 1⤋
3y+10=-2
3y=-2-10
3y=-12
y=-12/3
y=-4
2006-11-28 07:49:58 · answer #2 · answered by srirad 2 · 0⤊ 0⤋
add the negative 2 to the 10 and u end up with 3y=12 therefore y = 4
2006-11-27 23:01:01 · answer #3 · answered by twistoffate2099 4 · 0⤊ 0⤋
3y+10 = -2, subtract 10 from both sides,
3y + 10 - 10 = -2 - 10
3y = -12, divide both sides by 3
y = -4
2006-11-27 22:48:30 · answer #4 · answered by MrDanaH 2 · 1⤊ 0⤋
3y + 10 = -2 (given)
3y = -2 -10 (subtract 10 from both sides)
3y = -12 (simplify)
3y/3 = -12/3 (divide both sides by 3)
y = -4 (simplify) <--- there's your answer
2006-11-27 22:49:02 · answer #5 · answered by Peter 2 · 1⤊ 0⤋
3y+10=-2
because y = -4 -4 times 3 =1-12 and -12 + 10 = -2
please help answer my math question
2006-11-27 22:51:03 · answer #6 · answered by Anonymous · 0⤊ 0⤋
3y + 10 = -2
3y = -2 - 10
3y = -12
y = -12 / 3
Therefore, y = -4
2006-11-28 23:19:40 · answer #7 · answered by horensen 4 · 0⤊ 0⤋
3y = -10 -2
y = -12/3
y= -4
2006-11-27 22:48:49 · answer #8 · answered by shadab a 1 · 1⤊ 0⤋
3y=12
y=4
2006-11-27 22:47:45 · answer #9 · answered by raj 7 · 0⤊ 1⤋
3y + 10 = -2
3y = -10 -2
3y = -12
y = -12 / 3
y = -4
2006-11-27 22:50:39 · answer #10 · answered by M. Abuhelwa 5 · 1⤊ 0⤋