find the missing coordinate to complete the ordered pair solution to given linear equation y = 6x + 5
(0, ) (3, )
2006-11-27 14:11:57 · 4 answers · asked by shawntaelsey123 1 in Science & Mathematics ➔ Mathematics
.y = 6x + 5
(0, )
x=0
so y=5
(3, )
x=3, so y= 6(3) +5 =23
2006-11-27 14:15:50 · answer #1 · answered by Anonymous · 2⤊ 0⤋
For point a, you are given x = 7 but NO y. For point b, you are given y = -7 but NO x. Is this clear? You are also given a linear equation, which is: 5x - 2y=9. You will need to plug and chug using BOTH points. I will now use point a knowing that x = 7. So, I will plug 7 for x in the linear equation to find y for point a. Clear? We have: 5(7) - 2y=9 35 - 2y = 9 Next: subtract 35 FROM BOTH SIDES of the equation. We get: -2y = 9-35 -2y = -26 DIVIDE BOTH SIDES by -2 to find y. We get: y = -26/-2 y = 13. Point a = (7,13). +++++++++++++++++++++++++++ Next: Plug and chug to find point b. We have: 5x - 2(-7)=9 5x + 14 = 9 5x = 9-14 5x = -5 x = -5/5 x = -1 Point b = (-1, -7) Is this clear? Guido
2016-05-23 16:10:04 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Easy
y=y(x)=6x+5
y(x=0)=6(0) +5 = 5; therefore, (0,5)
y(x=3)=6(3)+5=18+5=23; therefore, (3,23)
2006-11-27 14:16:23 · answer #3 · answered by kellenraid 6 · 1⤊ 0⤋
(0,5);(3,23)
2006-11-27 14:17:48 · answer #4 · answered by raj 7 · 1⤊ 1⤋