how to i find parallel perpindicular or niether in this equation... PLEASE SHOW ALL WORK... I DONT KNOW HOW TO DO IT AND I NEED TO LEARN.... 3x+6y=30...4y+2x=9
2006-11-27 12:43:04 · 2 answers · asked by Derek Y 1 in Education & Reference ➔ Homework Help
The easiest way to do this would be to put the equations into slope-intercept form and compare the slopes. If the slopes are the same, the lines are parallel. If the slopes are the negative reciprocals of each other (like 2/3 and -3/2), they are perpendicular. If neither, then neither.
3x + 6y = 30
x + 2y = 10
2y = -x + 10
y = (-1/2)x + 5
Slope: -1/2
4y + 2x = 9
4y = -2x + 9
y = (-1/2)x + 9/4
Slope: -1/2
Your call here.
2006-11-27 12:49:55 · answer #1 · answered by Anonymous · 0⤊ 0⤋
First, you need to express the equations in the form y=mx + b, where m=slope and b=y-intercept
eqn 1: 3x+6y=30
6y=-3x+30
y=-3/6x+30/5
y=-1/2x+5
eqn 2: 4y+2x=9
4y=-2x+9
y=-2/4x+9/4
y=-1/2x+9/4
since the slopes of the 2 equations are equal (m=-1/2) then we are sure that the 2 equations are parallel
2006-11-27 20:54:23 · answer #2 · answered by Chris 2 · 0⤊ 0⤋