ALGEBRA1 HELP(SCATTERPLOTS, LINE OF BEST FIT, SLOPE INTERCEPT!!) hurry!?

Question

I'm In algebra 1(I skipped pre-algebra), so I've been having a ton of trouble in math. I made a scatterplot graph and I'm supposed to write two equations in slope intercept form! Here is some information: I used to different ropes(a thin and thick rope) I tied a knot into them and then remeasured them, each time adding one more knot. Here are some measurements: Thick knot: 0 knots-63 cm, 1 knot-57cm, 2 knots-51.5cm, 3 knots-46.5 cm.(what would be slope intercept form?)


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Also:
Thin kots: o knots-61cm, 1 knot-60cm, 2 knots-55cm, 3 knots-53cm.
(slope intercept form also)

THANK YOU ALL SO MUCH! YOU ARE LIFE SAVERS!!!

Answer 1

I'm not sure what you're asking so I can't give you an answer. However, here's how you need to set up your problem:

slope-intercept form is y=mx+b, right?

m=slope. Figure this out by m=y1-x1/y2-x2. This should be done after you figured out where on the graph your knots land. (x,y) (x,y)

The b stands for the y-intercept. The line that has the slope, where does it cross the y-axis? That's your y-intercept, or B.

Now put it together, get your calculator, and find out what y is.

Answer 2

Slope intercept kind is Y = mx + b, the position m is the slope and b is the y-intercept. you comprehend the slope is two, so Y = 2X + b. you want to discover B in spite of the indisputable fact that, so backwards confirm. 2 = 2(4) + B 2 = 8 + B -6 = B hence you get Y = 2X - 6 as your line.

Answer 3

Putting the values into my trusty TI-83 comes up with
y= - 5.5x+62.75 for the thick rope and
y= - 2.9x+61.6 for the thin rope. Now you do it!

Answer 4

y = mx + b

1. y = -6x + 61

2. y = -2x + 61