Solve by substitution:
1) 3x - 2y = 8
-6x + 4y = -16
2) 2x + y = 9
x - 3y = 22
2006-11-27 12:18:45 · 5 answers · asked by GMEN 1 in Science & Mathematics ➔ Mathematics
2. y = -2x+9
x - 3(-2x +9) = 22
x - 6x - 27 = 22
-5x - 27 = 22
-5x = 49
x = - 49/5
Do the same for #1
2006-11-27 12:23:09 · answer #1 · answered by J3Buckets 2 · 0⤊ 0⤋
3x-2y =8
-6x +4y = -16
Multiply the first equation by -2 and get
-6x+4y = -16, which is same as second equation.
The two equations are the same so no solution exists
2x +y =9
x -3y = 22 Multiply 1st equation by 3 to get:
6x +3y =27 Add this new equation to second equation, getting
7x=49
x=7
Substitute x=7 into 1st equation, getting:
2(7) +y =22
14 + y = 22
y = 22 - 14 =8
2006-11-27 20:31:23 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
1) can be any number
2) 2x + y = 9
x - 3y = 22
multiply the the top by (-3) so the y's can cancel out
[2x + y = 9] x 3
x - 3y = 22
-6x - 3y = -27
x - 3y = 22
now add 2 problems together and solve for x
-5x = -5
x = 1
now that you have x, plug that into either of the original problems to find y
2(1) + y = 9
2 + y = 9
y = 7
x = 1, y = 7 is your answer
2006-11-27 20:24:26 · answer #3 · answered by dizzawg16 3 · 0⤊ 0⤋
1. any real #,
2.x = 7
2006-11-27 20:21:51 · answer #4 · answered by dg24 2 · 0⤊ 0⤋
its B
2006-11-27 20:19:33 · answer #5 · answered by kingbling169 1 · 0⤊ 0⤋