A local hamburger shop sold 285 hamburgers and cheeseburgers on Tuesday. The number of cheeseburgers sold is two times the number of hamburgers sold. How many cheeseburgers did they sell?
2006-11-27 11:42:24 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
95 hamburgers
190 cheeseburgers. Let's put it into math.
c=number of cheeseburgers
h=number of hamburgers
c+h=285
c=2h (# of cheeseburgers=2 times number of hamburgers)
Plugging in 2h for c, we get
2h+h=285
3h=285
h=95.
Now, solving for c, we get 190 cheeseburgers sold. That's your answer.
I hope this helps.
2006-11-27 11:46:49 · answer #1 · answered by Aegor R 4 · 0⤊ 0⤋
one way:
h=hamburgers
c = cheeseburgers
cheeseburgers + hamburgers = 285
c + h = 285
c = 2 * hamburgers
c = 2 * h
substitute
(2h) + h = 285
3h =285
h = 95
now to find cheeseburgers
c = 2h
c = 2(95)
or
c + h =285
c + 95 = 285
either way, c =190
2006-11-27 11:49:56 · answer #2 · answered by Jess 2 · 0⤊ 0⤋
Hamburgers = x
Cheeseburgers = 2x
2x + x = 285
3x = 285
x =95
so 95 hanburgers and 190 cheesburgers
2006-11-27 11:46:29 · answer #3 · answered by Anonymous · 0⤊ 0⤋
c=hamburgers
2c=cheeseburgers
2c+c=285
3c=285
c=95 (hamburgers)
2c=2x95=190 (cheeseburgers)
2006-11-27 11:47:28 · answer #4 · answered by Joseph F 5 · 0⤊ 0⤋
190
2006-11-27 11:48:41 · answer #5 · answered by Anonymous · 0⤊ 0⤋
190
2006-11-27 11:47:15 · answer #6 · answered by ltntsg d 1 · 0⤊ 0⤋
hamburgers=x
cheeseburgers=2x
x+2x=285
3x=285
divide by 3
x=95
plug back in
(95)+2(95)=285
95 hamburgers
190 cheeseburgers
2006-11-27 11:47:17 · answer #7 · answered by lily 3 · 0⤊ 0⤋
hamburgers=h
cheeseburgers=c
c+h=285
c=2h
sub in one equation and you got it
2006-11-27 11:45:01 · answer #8 · answered by Ambino 4 · 0⤊ 0⤋