Please show your work.
2006-11-27 11:40:24 · 6 answers · asked by Chelsey 5 in Science & Mathematics ➔ Mathematics
Bruce discovered that the wishing well contained $9 in nickles and dimes and that there were 30 more dimes than nickels. How many coins of each type were there?
(40 nickels and 70 dimes is the answer)
2006-11-27 11:44:13 · update #1
Nickels = x
Dimes = x + 30
900 = 10(x+30) + 5(x)
900 = 10x + 300 + 5x
900 = 15x + 300
600 = 15x
x = 40
so, 40 nickels and 70 dimes
2006-11-27 11:44:13 · answer #1 · answered by Anonymous · 0⤊ 0⤋
well it is almost a guess and check here. You can start by saying that if there are 40 nickels ($2.00) then there would be 70 Dimes ($7.00).. wow, that is actually the answer :-} but yea, i would just kinda play a high low game with the nickels and dimes until you figure it out.
2006-11-27 19:45:08 · answer #2 · answered by ncaafan2 2 · 0⤊ 0⤋
2 dollars in nickels and 7dollars in dimes. 9 minus 3 =6 divived by thirds =2 dollars in nickels and 4dollars in dimes plus 3 dollars in dimes
2006-11-27 19:45:25 · answer #3 · answered by bayareart1 6 · 0⤊ 0⤋
70 dimes, 40 nickles. 30 dimes= $3.00, $9.00 - 3.00 = $6.00
10 dimes + 10 nickles = $1.50,
therefore: 40 dimes + 40 nickles = $6.00
2006-11-27 19:50:41 · answer #4 · answered by metal head 1 · 0⤊ 0⤋
n=nickels
d=dimes
you have to remember that a dime is worth $.1 and a nickel worth $.05
.05n+.1d=9
d=n+30
sub d into the other equation and you got it.
2006-11-27 19:43:18 · answer #5 · answered by Ambino 4 · 0⤊ 0⤋
I think the key phrase there is "YOUR work."
2006-11-27 19:42:59 · answer #6 · answered by EQ 6 · 0⤊ 1⤋