a worker has to move a 17 Kg brate along a flat floor in a warehouse. the coefficient of kinetic friction between the crate and the floor is 0.214. the worker pulls horicontally on a rop attached to the crate, with a 49.0 -N. what is the resultant acceleration of the crate?
2006-11-27 11:23:16 · 2 answers · asked by Andrew L 1 in Science & Mathematics ➔ Physics
is the answer to this question .785 meters over seconds squared?
2006-11-27 11:42:01 · update #1
First, calculate the force due to friction, F_f = uN, where u is the coefficient of kinetic friction and N is the normal force on the crate, which is equal to its weight. In this case, N = mg, so F_f = umg. The resultant force, F, on the crate will be the applied force, P = 49 N, less the force of friction. So F = P - F_f = P - umg. The acceleration is found by using the formula F = ma, or a = F/m, where we were given the mass m and we calculated the resultant force F.
2006-12-05 03:47:54 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
You are going to need to use the following formula: uk=Fk/Fn
To do that, you must first find the normal force, which in this case is the opposite of the weight.
After you have found the force due to friction (Fk), use the following: Fa - Fk = ma
Yes, that's the answer.
2006-11-27 19:29:21 · answer #2 · answered by Jeanne S 1 · 0⤊ 0⤋