number of small ones to the number of large ones was 1 to 6. How many were large and how many were small? Please show your work. Thank you!
2006-11-27 10:59:59 · 7 answers · asked by Chelsey 5 in Science & Mathematics ➔ Mathematics
let # of large ones = x and # of small ones = y
then x = 30+3y
and x=6y
=> 6y = 30 + 3y
=> 3y = 30
=> y = 10
and x = 6*10 = 60
2006-11-27 11:04:38 · answer #1 · answered by Manisha 4 · 0⤊ 0⤋
60 large and 10 small. Without the 30 more it has to be 1 to 3, so for 30 to make it up to 1 to 6 it has to start at 30 and 10.
2006-11-27 19:02:56 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The first step with word problems is to put the information into an equation. Let's call the number of small ones S and the number of large ones L. We're told that L = 3S + 30 and that L = 6S. Therefore we can say that 6S = 3S + 30. Subtract 3S from each side to get 3S = 30. Now divide by 3 to get the answer: S = 10. And since we know there are 6 times as many large ones, L = 60.
Ten small ones and sixty large.
2006-11-27 19:03:01 · answer #3 · answered by Amy F 5 · 0⤊ 0⤋
If you let x = the number of small ones
then 3x + 30 = number of large ones.
The ratio of small to large is then x/(3x + 30) which = 1/6
Cross multiply to get 6x = 3x + 30
Subtract 3x from both sides to get 3x = 30
Divide by 3 to get x = 10 small ones.
3 times 10 plus 30 = number of large ones
30 + 30 = 60 = number of large ones.
2006-11-27 19:09:21 · answer #4 · answered by Rich Z 7 · 0⤊ 0⤋
30*3
2006-11-27 19:02:54 · answer #5 · answered by JJ 3 · 0⤊ 1⤋
to big, to small
2006-11-27 19:01:38 · answer #6 · answered by conew508 1 · 0⤊ 1⤋
17!!!
2006-11-27 19:02:04 · answer #7 · answered by hadda_be_played_on_a_jukebox 3 · 0⤊ 1⤋