Consecutive numbers differ by 1.
If the first one is n, then the second one is n+1
That means the third one is the second number plus one (n+1)+1 = n+2
The fourth one is (n+2)+1 = n+3
and the fifth one is (n+3)+1 = n+4
Add them altogether
n + n+1 + n+2 + n+3 + n+4 = 5n + 10
2006-11-27 10:48:23
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answer #1
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answered by MsMath 7
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Sometimes examples are the best ways to demonstrate the things we don't understand: If I chose the number 10,11,12,13,14,
then the formula would be S=5(10) + 10. The reason this works is because each of those numbers is the same thing as 10, but each consecutive number adds 1, then 2, then 3, then 4. (11-1=10) (12-2=10) (13-3=10)(etc.) 1+2+3+4=10, thats where the 10 comes from
2006-11-27 18:49:21
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answer #2
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answered by Deliriouz 1
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s=5N + 10 is correct.
Let's consider 5 consecutive integers:
The smallest is n, the next is n+1, the next is n+2, and so on.
The sum will be
n+(n+1)+(n+2)+(n+3)+(n+4) =
5n+1+2+3+4=
5n+10!
There's your formula.
2006-11-27 18:49:54
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answer #3
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answered by Aegor R 4
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Smallest is n
Since consecutive, next is n+1
then, n+2,n+3,n+4
Sum S= n+(n+1)+(n+2)+(n+3)+(n+4)
= 5n+10!
2006-11-27 18:49:10
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answer #4
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answered by af12af3af 2
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its not 5n. 5n would be n times 5. you need consecutive numbers. so it would be n+(n+1)+(n+2)+(n+3)+(n+4).
2006-11-27 18:50:30
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answer #5
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answered by pimp 1
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it is a simplification
S = N + (N +1) + (N +2) + (N +3) + (N +4)
S = 5N + 10
2006-11-27 18:49:07
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answer #6
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answered by coop 2
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N is smallest number
N + 1 is the next number
N + 2 is the number after that one
N + 3 is the next
N + 4 is the 5th number
Add them together
5N + 10
2006-11-27 18:53:12
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answer #7
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answered by Steve P 5
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