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2006-11-27 10:06:46 · 2 answers · asked by dimachevelle 2 in Science & Mathematics Mathematics

2 answers

Use the chain rule: dy/dx = d/dx[(ln x)^x] = x(ln x)^(x-1)d/dx[ln x]

2006-11-27 10:10:59 · answer #1 · answered by kellenraid 6 · 0 0

Chain rule+d/dx(ln(x))... so instead of the previous answer:

(xln(x)^(x-1))/x

2006-11-27 10:19:59 · answer #2 · answered by Anonymous · 0 0

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