y=x^4-2/x^2?

5 ⤊

find the derivative of the funtion

2006-11-27 08:53:52 · 3 answers · asked by c205 1 in Science & Mathematics ➔ Mathematics

3 answers

Are there supposed to be parentheses somewhere?
Is it y = (x^4 -2) / x^2 or y = x^4 - (2/x^2)?
I'll go with the second one because that is what is implied if you have no parentheses.
y = x^4 - (2/x^2) = x^4 - 2x^-2, so
y' = 4x^3 + 4x^-3
y' = 4x^3 + 4/x^3

2006-11-27 09:06:32 · answer #1 · answered by MsMath 7 · 2⤊ 2⤋

y = x^4 - 2 / x^2
y = x^2 - 2x^(-2)
dy/dx = 2x + 4x^(-3) = 2x + 4/(x^3)

2006-11-28 22:13:16 · answer #2 · answered by Kemmy 6 · 1⤊ 0⤋

WTF??? are u like a math teacher or wat who in the HELL is gonna find the answer to that!? i mean SERIOUSLY!

2006-11-27 17:01:33 · answer #3 · answered by Anonymous · 2⤊ 2⤋