chemistry ?

Question

Ethylene glycol has a specific heat of 0.578 cal/(g * C) If 23.2 g of ethylene glycol absorbs 75.6 cal of energy, what will the temp increase be?

Answer 1

(specific heat)*(mass)*(change in temperature) = heat

[0.578 cal/(g*C)]*23.2g*(change in temperature) = 75.6 cal

now solve for change in temp, notice how units of cal and g cancle out.

http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html

no calculator at computer, so web site above calculated 5.64 C

Answer 2

>0.578 cal/(g * C) If 23.2 g of ethylene glycol absorbs 75.6 cal

0.578 = 75.6/(23.2 * C)
Solve for C

Answer 3

The temperature increase is equal to:

dT = dE/(m*q)
Where dT is the change in temperature, dE is the change in energy, m is the mass, and q is the specific heat.

dT = 75.6 / (23.2*.578) = 5.64 degrees Celcius.

I hope this helps!