pls help!!!.....?

Question

The velociraptor spots you 40 meters away and attacks, accelerating at 4 m/s^2 up to its top speed of 25 m/s. When it spots you, you begin to flee, quickly reaching your top speed of 6 m/s. How far can you get before you're caught and devoured????????? pls answer...

Answer 1

s = 1/2 at^2
40 m = 1/2 * 4 m/s^2 * t^2
80 m / 4 m/s^2 = t^2
20 = t^2
t = square root(20) = 4.47213595 seconds to go the 40 meters

dinosaur going (4.47213595 seconds) * 4 (m / (s^2)) = 17.8885438 m / s at that time

about another 2 seconds to get to max speed of 25 m/s

Answer 2

18 metres.