Solve the system by graphing.?

Question

4x + 2y = 10
y = 4

Answer 1

First equation:
4x + 2y = 10

Rearrange to get the y-term alone:
2y = 10 - 4x

Divide both sides by 2 to get it in slope-intercept form (y = mx + b):
y = -2x + 5

Now you can graph it by drawing a line through (0,5) as the y-intercept and have it go down at a slope of -2 through points (1,3), (2,1), (3,-1), etc.

For the second equation, draw a horizontal line for y = 4

You'll see they intersect at the point (½, 4). I've attached a graph of the two lines...

So your solution is:
x = 0.5 (or ½)
y = 4

Answer 2

Subtract 4x on both sides:
2y=-4x+10

Divide 2 on both sides:
y=-2x+5

You can either graph that equation on graphing paper by plugging in numbers for x and y or you can put this equation in the graphing calculator to see where they intersect at. The intersection is at (0.5,4).

Check:
4=-2(0.5)+5
4=-1+5
4=4

4=4

Answer 3

if y = 4, then x = ½. It is difficult to graph things in a text edit box. But you could graph these two lines by using the "y = mx + b" method. Solve the first equation for y, and then you'll have your slope and y-intersect.

y = -2x + 5

The slope = -2 and the y-intersect is at 5. The two lines will intersect at (½, 4).

Answer 4

your answer is where the lines intersect

plug y=4 into the first equation

4x + 2y = 10
4x + 2(4) = 10
4x + 8 = 10
4x = 2
x = 1/2

the lines intersect at (1/2, 4)

so your answer is

x = 1/2
y = 4

Answer 5

2y=-4x+10
y= -2x+5

basically just graph the equations and find the point where they intersect